for文を見直す

by yshrkn

JavaScript

var numbers = [2, 4, 3, 6, 2, 0, 1];

function hasOddNumber(numbers) {
	var isOdd = false;
  for (var i = 0, len = numbers.length; i < len; i++) {
		if (numbers[i] % 2 === 1) {
    	isOdd = true;
      break;
    }
  }
  return isOdd;
}


console.log("奇数が含まれているか？", hasOddNumber(numbers));