rowSumOddNumbers

by trentHarlem

JavaScript

// Given this pyramid of odd numbers, if
// rowSumOddNumber(2) //-> 3 + 5 = 8
// rowSumOddNumber(3) //-> 7 + 9 + 11 = 27
//              1
//           3     5
//        7     9    11
//    13    15    17    19
// 21    23    25    27    29
// etc...



const rowSumOddNumbers = n => n ** 3;

//const rowSumOddNumbers = n => Math.pow(n, 3);

/*  function rowSumOddNumbers(n) {
   return Math.pow(n,3);
 } */

console.log(rowSumOddNumbers(3));