Poker2023

Trying to see if I can adapt the 2012 solution for code golf.

by subskybox

HTML

<script src="https://cdn.jsdelivr.net/gh/eu81273/jsfiddle-console/console.js"></script>
<div id="output"></div>

CSS

body {
  /* font-size: 5em; */
}

JavaScript

var out = document.getElementById('output');
//console.log(out);


// Examining Suits
console.log("๐Ÿ‚ฒ๐Ÿ‚ป๐Ÿ‚ฝ๐Ÿ‚ฑ๐Ÿ‚พ".split(/(?:)/u).map(a=>a.charCodeAt(1)&48).every((v,i,a)=>v==a[0]));
console.log("๐Ÿƒ‰๐Ÿ‚ค๐Ÿ‚ด๐Ÿ‚ฎ๐Ÿƒž".split(/(?:)/u).map(a=>a.charCodeAt(1)&48).every((v,i,a)=>v==a[0]));
//Worth checking if a shift will result in distinct powers of two
//console.log("๐Ÿƒ‰๐Ÿ‚ค๐Ÿ‚ด๐Ÿ‚ฎ๐Ÿƒž".split(/(?:)/u).map(a=>a.charCodeAt(1)>>4&3));

// Examining Ranks
//console.log("๐Ÿ‚ฒ๐Ÿ‚ป๐Ÿ‚ฝ๐Ÿ‚ฑ๐Ÿ‚พ".split(/(?:)/u).map(a=>a.charCodeAt(1)&15));
//Corrected for French playing cards
console.log("๐Ÿ‚ฒ๐Ÿ‚ป๐Ÿ‚ฝ๐Ÿ‚ฑ๐Ÿ‚พ".split(/(?:)/u).map(a=>(a=a.charCodeAt(1)&15)<12?a:a-1));


//for (let arg of arguments)
  //  print(arg.split(/(?:)/u).map(a=>(a=a.charCodeAt(1)&15)<12?a:a-1));
  
  for(a of ["๐Ÿ‚ฒ๐Ÿ‚ป๐Ÿ‚ฝ๐Ÿ‚ฑ๐Ÿ‚พ", "๐Ÿƒ‰๐Ÿ‚ค๐Ÿ‚ด๐Ÿ‚ฎ๐Ÿƒž"]) {
    wave1 = a.split(/(?:)/u).map(a=>[(b=a.charCodeAt(1)&15)<12?b:b-1,(1<<b)]);
    console.log(wave1);
    //wave2 = wave1.reduce((accumulator, currentValue) => accumulator + parseInt(currentValue),0);
    wave2 = wave1.reduce((r, a) => r.map((b, i) => a[i] + b));
    console.log(wave2);
  }