JSFiddle - React, Tailwind, and code Playground

by nickkell

HTML

<!-- another version - flat style with animated hover effect -->
<div class="breadcrumb flat">
	<a href="#" class="active">Browse</a>
	<a href="#" class="active">Compare</a>
	<a href="#">Order Confirmation</a>
	<a href="#">Checkout</a>
</div>

CSS

@import url(http://fonts.googleapis.com/css?family=Merriweather+Sans);

* {margin: 0; padding: 0;}

html, body {min-height: 100%;}

body {
	text-align: center;	
	font-family: 'Merriweather Sans', arial, verdana;
}

.breadcrumb {
	/*centering*/
	display: inline-block;
	box-shadow: 0 0 15px 1px rgba(0, 0, 0, 0.35);
	overflow: hidden;
	border-radius: 5px;
	/*Lets add the numbers for each link using CSS counters. flag is the name of the counter. to be defined using counter-reset in the parent element of the links*/
	counter-reset: flag; 
}

.breadcrumb a {
	text-decoration: none;
	outline: none;
	display: block;
	float: left;
	font-size: 12px;
	line-height: 36px;
	color: white;
	/*need more margin on the left of links to accomodate the numbers*/
	padding: 0 10px 0 40px;
	background: #666;
	background: linear-gradient(#666, #333);
	position: relative;
}
/*since the first link does not have a triangle before it we can reduce the left padding to make it look consistent with other links*/
.breadcrumb a:first-child {
	padding-left:10px;
	border-radius: 5px 0 0 5px; /*to match with the parent's radius*/
}

.breadcrumb a:last-child {
	border-radius: 0 5px 5px 0; /*this was to prevent glitches on hover*/
	padding-right: 20px;
}

/*hover/active styles*/
.breadcrumb a.active {
	background: #333;
	background: linear-gradient(#333, #000);
}
.breadcrumb a.active:after {
	background: #333;
	background: linear-gradient(135deg, #333, #000);
}

/*adding the arrows for the breadcrumbs using rotated pseudo elements*/
.breadcrumb a:after {
	content: '';
	position: absolute;
	top: 0; 
	right: -18px; /*half of square's length*/
	/*same dimension as the line-height of .breadcrumb a */
	width: 36px; 
	height: 36px;
	/*as you see the rotated square takes a larger height. which makes it tough to position it properly. So we are going to scale it down so that the diagonals become equal to the line-height of the link. We scale it to 70.7% because if square's: 
	length = 1; diagonal = (1^2 +...