d3 force graph no links
by jonathanmh
HTML
<script src="https://d3js.org/d3.v7.min.js"></script>
<div id="chart"></div>
JavaScript
function ForceGraph({
nodes, // an iterable of node objects (typically [{id}, …])
links // an iterable of link objects (typically [{source, target}, …])
}, {
nodeId = d => d.id, // given d in nodes, returns a unique identifier (string)
nodeGroup, // given d in nodes, returns an (ordinal) value for color
nodeGroups, // an array of ordinal values representing the node groups
nodeTitle, // given d in nodes, a title string
nodeFill = "currentColor", // node stroke fill (if not using a group color encoding)
nodeStroke = "#fff", // node stroke color
nodeStrokeWidth = 1.5, // node stroke width, in pixels
nodeStrokeOpacity = 1, // node stroke opacity
nodeRadius = 5, // node radius, in pixels
nodeStrength,
linkSource = ({
source
}) => source, // given d in links, returns a node identifier string
linkTarget = ({
target
}) => target, // given d in links, returns a node identifier string
linkStroke = "#999", // link stroke color
linkStrokeOpacity = 0.6, // link stroke opacity
linkStrokeWidth = 1.5, // given d in links, returns a stroke width in pixels
linkStrokeLinecap = "round", // link stroke linecap
linkStrength,
colors = d3.schemeTableau10, // an array of color strings, for the node groups
width = 640, // outer width, in pixels
height = 400, // outer height, in pixels
invalidation // when this promise resolves, stop the simulation
} = {}) {
// Compute values.
const N = d3.map(nodes, nodeId).map(intern);
const LS = d3.map(links, linkSource).map(intern);
const LT = d3.map(links, linkTarget).map(intern);
if (nodeTitle === undefined) nodeTitle = (_, i) => N[i];
const T = nodeTitle == null ? null : d3.map(nodes, nodeTitle);
const G = nodeGroup == null ? null : d3.map(nodes, nodeGroup).map(intern);
const W = typeof linkStrokeWidth !== "function" ? null : d3.map(links, linkStrokeWidth);
const L = typeof linkStroke !== "function"...