isPalindrome #2

by Abhishek Kumar

JavaScript

function isPalindrome(word) {
  var re = /[^A-Za-z0-9]/g;
  word = word.toLowerCase().replace(re, '');
  var len = word.length;
  for (var i = 0; i < len / 2; i++) {
    if (word[i] !== word[len - 1 - i]) {
      return false;
    }
  }
  return true;
}
console.log(isPalindrome('Deleveled'))
console.log(isPalindrome('adam'))