Edit in JSFiddle

var myArray = ['Boston', 'New York', 'Chicago', 'Miami', 'Los Angeles', 'Dallas', 'Seattle'];

$(myArray).each(function(i, item){
	$("#output").append($("<li>").append(item));
});


$.each(myArray, function(i, item){
	$("#output2").append($("<li>").append(item));
});
<!-- Easy jQuery - working with .each() - #11 -->
<p>
    Welcome to the 11th Easy jQuery Tutorial, part of <a href="http://www.easyprogramming.net">EasyProgramming.net</a>. In this tutorial, let's learn working with the .each() method in jQuery.
</p>
<p>
    This is very similar to the JavaScript forEach loop as shown on <a href="https://www.easyprogramming.net/javascript/js_array_forEach_method.php">Easy Programming</a>.
</p>

<p>
The <code>.each()</code> loop can be written two different ways. The frst way lets you select an array object and pass in a call backfunction as the one and only argument as shown below:
</p>
<pre>
  $(array).each(function(index, item){
    execute code;
    the 'item' is the actual value;
    'index' is the index number (e.g. i);
  })
</pre>

<p>
The second way lets you select jQuery as the object itself and pass in two arguments. The first being the array and second being the callback function. 
</p>
<pre>
  $.each(array, function(index, item){
    execute code;
    the 'item' is the actual value;
    'index' is the index number (e.g. i);
  })
</pre>

<h2>
    Let's practice:
</h2>

<ol id="output"></ol>

<ol id="output2"></ol>

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