// Задача. Написать такую add, чтобы 0 + add(x1)(x2)(...)(xn) => сумма всех xi.
// это то, что получилось вчера
function mutableAdd(x) {
var sum = x;
function f(y) {
sum += y;
return f;
};
f.valueOf = function() {
return sum;
};
return f;
}
// а так было бы круче
function immutableAdd(x) {
function f(y) {
return immutableAdd(x + y);
};
f.valueOf = function() {
return x;
};
return f;
}
function runExample(add) {
// с базисом add
var v1 = add(1);
// с базисом v1
var v3 = v1(1)(1);
var v2 = v1(1);
// с базисом v3
var v5 = v3(2);
var v4 = v3(1);
console.log(add.name, v1, v2, v3, v4, v5);
}
// В mutableAdd каждый вызов меняет и возвращает старое состояние
runExample(mutableAdd);
// В immutableAdd каждый вызов создает и возвращает новое состояние
runExample(immutableAdd);
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