test if compounding

evaluate valid number or string

by David McClelland

HTML

<div id="banner-message">
  <p>Hello World</p>
  <button>Change color</button>
</div>

CSS

body {
  background: #20262E;
  padding: 20px;
  font-family: Helvetica;
}

#banner-message {
  background: #fff;
  border-radius: 4px;
  padding: 20px;
  font-size: 25px;
  text-align: center;
  transition: all 0.2s;
  margin: 0 auto;
  width: 300px;
}

button {
  background: #0084ff;
  border: none;
  border-radius: 5px;
  padding: 8px 14px;
  font-size: 15px;
  color: #fff;
}

#banner-message.alt {
  background: #0084ff;
  color: #fff;
  margin-top: 40px;
  width: 200px;
}

#banner-message.alt button {
  background: #fff;
  color: #000;
}

JavaScript

// find elements
var banner = $("#banner-message")
var button = $("button")

// handle click and add class
button.on("click", function() {
  banner.addClass("alt");
  compoundIfTest('<bad/>');
})

function compoundIfTest(value) {
  
  var defaultValue = 999;
  var type = 'string';
  var regex = /^[<>"']/g;

  // validate properties with number or string baseType against injection
  if (((type === 'number' || type === 'integer' || type === 'long') &&
      isNaN(parseInt(value, 10))) || type === 'string' && regex.exec(value)) {
    alert(type + ': ' + defaultValue);
    return;
  }
  alert(type + ': ' + value);
}