//Calculate the Sum of an Array Using the forEach
const sumMe = [1,4,6,7,8,10];
let sumVar = 0;
sumMe.forEach(sumItem => {
sumVar += sumItem;
})
/* console.log(sumVar); */
//Math.min() and Math.max() in JavaScript.
const numbers = [10, 20, 23, 5, 40, 54, 80];
const minValue = Math.min(...numbers);
const maxValue = Math.max(...numbers);
console.log(Math.min(4,10));
console.log(`Minimum value is ${minValue} and maximum value is ${maxValue}`);
const originalArray = [1, 2, 3];
const copyArray = [...originalArray];
console.log(originalArray); // Output: [1, 2, 3]
console.log(copyArray); // Output: [1, 2, 3]
originalArray.push(4);
console.log(originalArray); // Output: [1, 2, 3, 4]
console.log(copyArray); // Output: [1, 2, 3]
//NESTED FOR LOOP WORKING
for(var i=4;i<6;i++){
for(var j=4;j<5;j++){
// console.log(i,j);
}
}
//4 4
//5 4
//Find the Index of the First Occurrence in a String
let haystack = "sadbutsad", needle = "sad";
console.log("First Occurrence", haystack.indexOf(needle));
//We have numbers array like [2,4,3,5,6,1]; should the addition of any two numbers be less than the largest number of that array in js?
function isSumLessThanLargest(numbers) {
const largestNumber = Math.max(...numbers);
for (let i = 0; i < numbers.length-1; i++) {
console.log(i,numbers[i]," ------ ");
for (let j = i + 1; j < numbers.length; j++) {
console.log("Inner FOr ",j,numbers[i], numbers[j],numbers[i] + numbers[j] );
/* if (numbers[i] + numbers[j] >= largestNumber) {
return numbers[i] +' '+numbers[j];
}*/
}
}
return true;
}
const numbersArray = [9,4,3,5,8];
//const result = isSumLessThanLargest(numbersArray);
//console.log(result); // Output: true
//SetTimeOut With Var
//By the time the setTimeout function runs (after the loop has completed), the value of y is 5 because the loop has finished, and y is shared among all the setTimeout callbacks.
//The setTimeout...
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