JSFiddle - React, Tailwind, and code Playground

JavaScript

let brands1 = ['Ford', 'Kia', 'VW', 'Audi'];
let brands2 = ['Audi', 'Kia'];
// Find 'every' brand intersection. 
// Meaning all elements inside 'brands2' must be present in 'brands1':
let intersectionEvery = brands2.every( brand => brands1.includes(brand) );
if (intersectionEvery) {
	const differenceList = brands1.filter(brand => !brands2.includes(brand));
	console.log('difference list:', differenceList);
  const commonList = brands1.filter(brand => brands2.includes(brand));
	console.log('common list:', commonList);
}