subarray in array

by Diana Lemen

JavaScript

const A = [3, 0, 3, 0, 5, 1, 1, 2];
const B = [3, 0, 5, 1];

let test = false;
for (let j = 0; j < B.length; j++) {
  if (A[j] !== B[j]) {
    A.shift();
    j = 0;
  } else {
    if (j === B.length - 1) {
      test = true;
    }
  }
}

console.log(test)