working jqGrid to convert JSON data to HTML table

quickly convert JSON data to jqGrid. Sorting column is one of the cool feature about jqGrid library.

HTML

<link rel="stylesheet" href="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8.14/themes/base/jquery-ui.css">
<link rel="stylesheet" href="http://trirand.com/blog/jqgrid/themes/ui.jqgrid.css">
<script src="http://trirand.com/blog/jqgrid/js/i18n/grid.locale-en.js"></script>
<script src="http://trirand.com/blog/jqgrid/js/jquery.jqGrid.min.js"></script>
<table id="grid"></table>

JavaScript

var data = "https://w3.ibm.com/tools/cio/forms/secure/org/data/d317d77b-56a2-4194-843d-56baab0bf05a/F_Form1=text/xml";

var names = ["Title"];
var mydata = [];

for (var i = 0; i < data.length; i++) {
    mydata[i] = {};
    for (var j = 0; j < data[i].length; j++) {
        mydata[i][names[j]] = data[i][j];
    }
}

for (var i = 0; i <= mydata.length; i++) {
    $("#grid").jqGrid('addRowData', i + 1, mydata[i]);
}

/*
$("#grid").jqGrid('setGridParam', {onSelectRow: function(rowid,iRow,iCol,e){alert('row clicked');}});
*/
$("#grid").jqGrid('setGridParam', {ondblClickRow: function(rowid,iRow,iCol,e){alert('double clicked');}});