Destroying subviews
by nikoshr
HTML
<script src="http://underscorejs.org/underscore-min.js"></script>
<script src="http://backbonejs.org/backbone-min.js"></script>
<script src="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8.23/jquery-ui.min.js"></script>
<script id="tpl-table" type="text/template">
<table>
<thead>
<tr>
<th>Row</th>
<th>Name</th>
</tr>
</thead>
<tbody>
<% _(children).each(function(model) { %>
<tr id='<%= model.cid %>'>
<td><%= model.row %></td>
<td><%= model.name %></td>
</tr>
<% }); %>
</tbody>
</table>
</script>
<div id='view'></div>
JavaScript
var BaseView, ItemView, ListView, i, data, view;
BaseView = Backbone.View.extend({
initialize: function () {
// list of subviews
this.views = [];
},
// handle the subviews
// override to destroy jQuery plugin instances
unstage: function () {
if (!this.views) {
return;
}
var i, l = this.views.length;
for (i = 0; i < l; i = i + 1) {
this.views[i].destroy();
}
this.views = [];
},
// override to setup jQuery plugin instances
stage: function () {
},
// destroy the view
destroy: function () {
this.unstage();
this.remove();
this.off();
if (this.collection) {
this.collection.off(null, null, this);
}
if (this.model) {
this.model.off(null, null, this);
}
}
});
ItemView = BaseView.extend({
events: {
"click td": "show"
},
show: function () {
console.log(this.model.get("name"));
},
stage: function () {
this.$el.draggable({
revert: "invalid",
helper: "clone"
});
},
unstage: function () {
this.$el.draggable('destroy');
BaseView.prototype.unstage.call(this);
}
});
ListView = BaseView.extend({
render: function () {
var data, html, $table, template = this.options.template;
data = this.collection.map(function (model) {
return _.extend(model.toJSON(), {
cid: model.cid
});
});
html = this.options.template({
children: data
});
$table = $(html);
this.unstage();
this.collection.each(function (model) {
var subview = new ItemView({
el: $table.find("#" + model.cid),
model: model
});
subview.stage();
this.views.push(subview);
}, this);
...