Edit in JSFiddle

<div id="IP">
</div>
<div id="Country">
</div>
<div id="loc">
</div>

<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<script>

function ipLookUp () {
 $.ajax({
        url: 'https://ipinfo.io',
        dataType: 'jsonp',       
        jsonp: 'callback',
    })
  .then(
      function success(response) {
         $("#IP").html(response.ip);
          $("#Country").html(response.country);
           $("#loc").html(response.loc);
         console.log(response.ip, response.country,response.loc);

      },

      function fail(data, status) {
          console.log('Request failed.  Returned status of',
                      status);
      }
  );
}
ipLookUp()
</script>