Edit in JSFiddle

var array = [];

Array.prototype.indexOf = function (elt) {
    var len = this.length;

    var from = Number(arguments[1]) || 0;

    for (; from < len; from++) {
        if (from in this && this[from] === elt)
            return from;
    }
    return -1;
};
function columInfo(name) {
    this.Name = name;
}
array.push(new columInfo("Name"));
array.push(new columInfo("ID"));
array.push(new columInfo("StartTime"));
var name = array[0];
index = array.indexOf(name);
console.log(index);

<br/><p><font size="3"><b>Source for this<a  target="_blank"href="http://jqfaq.com/how-to-workaround-inarray-issues/"</a> JQFaq Question</b></font></p>

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